There are three friend living on the straight line Ox in Lineland. The first friend lives at the point x1, the second friend lives at the pointx2, and the third friend lives at the point x3. They plan to celebrate the New Year together, so they need to meet at one point. What is the minimum total distance they have to travel in order to meet at some point and celebrate the New Year?
It's guaranteed that the optimal answer is always integer.
The first line of the input contains three distinct integers x1, x2 and x3 (1 ≤ x1, x2, x3 ≤ 100) — the coordinates of the houses of the first, the second and the third friends respectively.
Print one integer — the minimum total distance the friends need to travel in order to meet together.
7 1 4
6
30 20 10
20
代码:
#include<cstdio>
int main(){
int a,b,c,t;
scanf("%d%d%d",&a,&b,&c);
if(a>b){
t=a;a=b;b=t;
}
if(a>c){
t=a;a=c;c=t;
}
if(b>c){
t=b;b=c;c=t;
}
printf("%d",c-a);
return 0;
}
三个朋友分别居住在直线上的不同位置,他们计划新年聚会。为了使总行走距离最短,需要找到一个相遇点。本篇介绍如何通过简单的算法找出这个最优位置。
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