整数转换成罗马数字[字符串处理]

题目链接
给定一个整数 numnum，将整数转换成罗马数字。

如 1,2,3,4,51,2,3,4,5 对应的罗马数字分别为I，II，III，IV，V等，更详细的说明见此 链接。

输入格式

第一行输入一个整数num(1≤num≤3999)。

输出格式

输出 num 对应的罗马数字。

样例输入

123
样例输出

CXXIII

#include<bits/stdc++.h>
using namespace std;
int main(){
    int a,arr[5],k;
    char* str[5][10] = {
	    //注意一点一定要定义为char* 类型,即指针类型,否则的话,char类型会因为超过一个字符而报错
        //将1,2,3,...,7,8,9,10,20,30...100,200,1000,2000,3000这些整数保存到一个二维数组中
        {"","","","","","","","","",""},
        {"","I","II","III","IV","V","VI","VII","VIII","IX"},
        {"","X","XX","XXX","XL","L","LX","LXX","LXXX","XC"},
        {"","C","CC","CCC","CD","D","DC","DCC","DCCC","CM"},
        {"","M","MM","MMM"}
    };
    scanf("%d",&a);
    k = 1;
    while(a){
        arr[k++] = a % 10;
        a /= 10;
    }
    for(int i = k - 1;i >= 1;i--)
        printf("%s",str[i][arr[i]]);
    printf("\n");
    return 0;
}