一、原理
定义一个数组,由两个指针分别指向数组的首部和尾部,其分别代表两个栈的栈顶
二、代码实现
package com.jp.yuanfudao.prepare.mianshi.test7;
/**
* @program: mianjing
* @description: 一个数组实现两个栈
* @author: CoderPengJiang
* @create: 2020-06-26 18:58
**/
public class Main {
public static void main(String[] args) {
DoubleStack doubleStack=new DoubleStack(8);
doubleStack.push1(1);
doubleStack.push1(3);
doubleStack.push1(4);
doubleStack.push1(5);
doubleStack.push2(9);
doubleStack.push2(8);
doubleStack.push2(7);
doubleStack.push2(6);
doubleStack.print_stack1();
doubleStack.print_stack2();
System.out.println(doubleStack.getLength());
}
}
class DoubleStack {
//两个栈的长度
private int length;
private int top1,top2;
private int[] array;
public int getLength() {
return length;
}
public void setLength(int length) {
this.length = length;
}
public int getTop1() {
return top1;
}
public void setTop1(int top1) {
this.top1 = top1;
}
public int getTop2() {
return top2;
}
public void setTop2(int top2) {
this.top2 = top2;
}
public int[] getArray() {
return array;
}
public void setArray(int[] array) {
this.array = array;
}
public DoubleStack(int length) {
this.length = length;
array=new int[length];
top1=-1;
top2=length;
}
//定义两个栈的push和pop
public boolean push1(int a){
if (top1+1==top2){
return false;
}else{
array[++top1]=a;
return true;
}
}
public boolean push2(int a){
if (top2-1==top1){
return false;
}else {
array[--top2]=a;
return true;
}
}
public boolean pop1(){
if (top1==-1){
return false;
}else {
top1--;
return true;
}
}
public boolean pop2(){
if (top2==length){
return false;
}else {
top2--;
return true;
}
}
public void print_stack1(){
if (top1==-1){
System.out.println(
"stack1 is empty!!!"
);
}else {
for (int i=0;i<=top1;i++){
System.out.print(array[i]+" ");
}
System.out.println();
}
}
public void print_stack2(){
if (top2==length){
System.out.println(
"stack2 is empty!!!"
);
}else {
for (int i=length - 1;i>=top2;i--){
System.out.print(array[i]+" ");
}
System.out.println();
}
}
}