Python实现int函数

import re
from functools import reduce
DIGITS = {'0':0,'1':1,'2':2,'3':3,'4':4,'5':5,'6':6,'7':7,'8':8,'9':9} 
def other2int(text):
	if not text:
		print('不能传入空值')
		return 
	if isinstance(text, str):
		if re.findall('\D', text):
			print('数据中包含除数字之外的字符，不能进行转化')
			return 
		m = map(lambda x:DIGITS[x], text)
		return reduce(lambda x,y=0:x*10+y,m)
	elif isinstance(text, float):
		m = map(lambda x:DIGITS[x], '%d'%text)
		return reduce(lambda x,y=0:x*10+y,m) 
	elif isinstance(text, int):
		return text
	else:
		print('该类型数据不能转化为整数')
# 测试
for text in [123.45, 1.0 ,'123', '1', '123bb', '1.23', 123]:
	result = other2int(text)
	print(type(result))
	print(result)