02-线性结构2 一元多项式的乘法与加法运算 (20 分)

本文介绍了一种使用链表结构实现一元多项式乘法和加法的方法。通过定义节点结构体,文章详细阐述了读取输入、进行多项式运算及输出结果的具体步骤。此算法适用于数学计算和计算机科学教育。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

设计函数分别求两个一元多项式的乘积与和。

输入格式:

输入分2行,每行分别先给出多项式非零项的个数,再以指数递降方式输入一个多项式非零项系数和指数(绝对值均为不超过1000的整数)。数字间以空格分隔。

输出格式:

输出分2行,分别以指数递降方式输出乘积多项式以及和多项式非零项的系数和指数。数字间以空格分隔,但结尾不能有多余空格。零多项式应输出0 0

输入样例:

4 3 4 -5 2  6 1  -2 0
3 5 20  -7 4  3 1

输出样例:

15 24 -25 22 30 21 -10 20 -21 8 35 6 -33 5 14 4 -15 3 18 2 -6 1
5 20 -4 4 -5 2 9 1 -2 0

 

#include<cstdio>
#include<cstdlib>
typedef struct Node *Polynomial;
struct Node{
	int coef;
	int exp;
	Polynomial link;
};
void attach(int coef, int exp, Polynomial *pRear){
	Polynomial p;
	p = (Polynomial)malloc(sizeof(struct Node));
	p->coef = coef;
	p->exp = exp;
	(*pRear)->link = p;
	*pRear = p;
}
Polynomial read(){
	int n, a, b;
	Polynomial Rear, p, t;
	p = (Polynomial)malloc(sizeof(struct Node));
	p->link = NULL;
	Rear = p;
	scanf("%d", &n);
	while(n--){
		scanf("%d%d", &a, &b);
		attach(a, b, &Rear);
	}
	Rear->link = NULL;
	t = p; p = p->link; free(t);
	return p;
} 
Polynomial add(Polynomial p1, Polynomial p2){
	Polynomial p, t1, t2, Rear, t;
	t1 = p1; t2 = p2;
	p = (Polynomial)malloc(sizeof(struct Node));
	Rear = p;
	p->link = NULL;
	while(t1 && t2){
		if(t1->exp == t2->exp){
			int c = t1->coef + t2->coef;
			if(c)attach(c, t1->exp, &Rear);
			t1 = t1->link;
			t2 = t2->link;
		}else if(t1->exp < t2->exp){
			Rear->link = t2;
			Rear = t2;
			t2 = t2->link;
		}else{
			Rear->link = t1;
			Rear = t1;
			t1 = t1->link;
		}
	}
	Rear->link = t1 ? t1 : t2;
	t = p; p = p->link; free(t);
	return p;
}
Polynomial multi(Polynomial p1, Polynomial p2){
	Polynomial p, t1, t2, Rear, temp;
	int e, c;
	if(!p1 || !p2)return NULL;
	p = (Polynomial)malloc(sizeof(struct Node));
	p->link = NULL;
	Rear = p;
	t1 = p1; t2 = p2;
	while(t2){
		e = t1->exp + t2->exp;
		c = t1->coef * t2->coef;
		attach(c, e, &Rear);
		t2 = t2->link;
	}
	t1 = t1->link;
	while(t1){
		t2 = p2; Rear = p;
		while(t2){
			e = t1->exp + t2->exp;
			c = t1->coef * t2->coef;
			while(Rear->link && Rear->link->exp > e)Rear = Rear->link; //注意要判断Rear->next是否存在
			if(Rear->link && Rear->link->exp == e){
				if(Rear->link->coef + c){
					Rear->link->coef += c;
				}else{
					temp = Rear->link;
					Rear->link = temp->link;
					free(temp); 
				}
			}else{
				temp = (Polynomial)malloc(sizeof(struct Node));
				temp->exp = e;
				temp->coef = c;
				temp->link = Rear->link;
				Rear->link = temp;
			}
			t2 = t2->link;
		}
		t1 = t1->link;
	}
	Rear->link->link = NULL; //注意点
	temp = p; p = p->link; free(temp);
	return p;
}
void print(Polynomial p){
	Polynomial t = p;  
	if(t == NULL){
		printf("0 0\n");
		return;
	}
	else{
		while(t){
			if(t->link != NULL)printf("%d %d ", t->coef, t->exp);
			else printf("%d %d\n", t->coef, t->exp);
			t = t->link;
		}
	}
}
int main(){
	Polynomial p1, p2, p3, p4;
	p1 = read();
	p2 = read();
	p3 = multi(p1, p2);
	print(p3);
	p4 = add(p1, p2);
	print(p4);
	return 0;
}

 

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值