【Codewars python 4kyu】：Total increasing or decreasing numbers up to a power of 10

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最新推荐文章于 2024-10-03 19:13:18 发布

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分类专栏： Codewars 文章标签： codewars python 4kyu Total increasing or decreasing

本文链接：https://blog.youkuaiyun.com/qq_36362028/article/details/100566563

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该博客讨论了如何计算10的x次幂以下所有递增或递减数字的总数。递增和递减数字的定义被给出，并提供了示例。博主指出，对于较小的数字，可以很容易地确定哪些是递增或递减的，但对于更大的数字，需要更高效的算法。文章还提示了一个暴力求解方法可能不适用于更大的测试用例，并提供了一组示例数据来展示函数应该如何工作。

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问题描述：

Let's define increasing numbers as the numbers whose digits, read from left to right, are never less than the previous ones: 234559 is an example of increasing number.

Conversely, decreasing numbers have all the digits read from left to right so that no digits is bigger than the previous one: 97732 is an example of decreasing number.

You do not need to be the next Gauss to figure that all numbers with 1 or 2 digits are either increasing or decreasing: 00, 01, 02, ..., 98, 99 are all belonging to one of this categories (if not both, like 22 or 55): 101 is indeed the first number which does NOT fall into either of the categories. Same goes for all the numbers up to 109, while 110 is again a decreasing number.

Now your task is rather easy to declare (a bit less to perform): you have to build a function to return the total occurrences of all the increasing or decreasing numbers below 10 raised to the x

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