问题
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
Example:
Input: 1->2->4, 1->3->4
分析
又是一道链表的题目。
归并即可。
代码
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def mergeTwoLists(self, l1, l2):
"""
:type l1: ListNode
:type l2: ListNode
:rtype: ListNode
"""
head = ListNode(0)
l3 = head
while l1 != None or l2 != None:
if l1 != None and l2 != None:
if l1.val < l2.val:
l3.next = ListNode(l1.val)
l3 = l3.next
l1 = l1.next
else:
l3.next = ListNode(l2.val)
l3 = l3.next
l2 = l2.next
else:
while l1 != None:
l3.next = ListNode(l1.val)
l3 = l3.next
l1 = l1.next
while l2 != None:
l3.next = ListNode(l2.val)
l3 = l3.next
l2 = l2.next
return head.next