Description
Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal
digits.
Input
The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.
Output
For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.
Sample Input
2 6 19 0
Sample Output
10 100100100100100100 111111111111111111
#include<stdio.h> #include<string.h> #include<stdlib.h> #include<math.h> #include<queue> #include<iostream> #include<algorithm> using namespace std; #define N 11000 int n, found; void DFS(long long t , int k) { if(k==20 || found==1) return ; if(t%n==0) { found=1; printf("%I64d\n",t); return ; } DFS(t*10,k+1); DFS(t*10+1,k+1); } int main() { while(scanf("%d",&n),n) { found=0; DFS(1,1); } return 0; }