Given a string s, partition s such that every substring of the partition is a palindrome.
Return all possible palindrome partitioning of s.
Example:
Input: “aab”
Output:
[
[“aa”,“b”],
[“a”,“a”,“b”]
]
C++
vector<vector<string>> partition(string s) {
//将一个字符串拆分成回文串
vector<vector<string>> res;
vector<string> out;
helper(s,0,out,res);
return res;
}
void helper(string s,int start,vector<string>& out,vector<vector<string>>& res)
{
if(start == s.size())
{
res.push_back(out);
return;
}
for(int i = start;i < s.size();++i)
{
if(!IsPalin(s,start,i))continue;
out.push_back(s.substr(start,i-start+1));
helper(s,i+1,out,res);
out.pop_back();
}
}
bool IsPalin(string s,int start,int end)
{
while(start <= end)
{
if(s[start] != s[end])
return false;
else
{
++start;
--end;
}
}
return true;
}