【NEEPU OJ】1003--A+B Problem(2)

这是一个针对初学者设计的简单加法计算器题目解析,包含C++和Java两种语言的实现代码示例,适合编程入门者练习基本的输入输出和算术运算。
描述

Your task is to Calculate a + b.
Too easy?! Of course! I specially designed the problem for acm beginners.
You must have found that some problems have the same titles with this one, yes, all these problems were designed for the same aim.

输入

The input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line.

输出

For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.

输入样例 1

1 5
10 20

输出样例 1

6
30

输入样例 2

1 1
2 2
3 3

输出样例 2

2
4
6

来源

hdu


代码

1.cpp

#include <cstdio>
using namespace std;

int main(){
    int a, b;
    while(~scanf("%d %d", &a, &b)){
        printf("%d\n", a + b);
    }
    return 0;
}

2.java

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int a, b;
        while (sc.hasNextInt()) {
            a = sc.nextInt();
            b = sc.nextInt();
            System.out.println(a + b);
        }
        sc.close();
    }
}
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