hackerrank String 5 Text Alignment_you are given a partial code that is used for gene-优快云博客

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该任务要求根据给定的厚度值，用rjust, ljust或center填充空白以生成HackerRank Logo。输入是奇数厚度值，输出符合要求的Logo。" 133371900,11421163,微信小程序路由与页面跳转实战指南,"['微信小程序', '小程序开发', '路由管理', '页面跳转']

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Task

You are given a partial code that is used for generating the HackerRank Logo of variable thickness.
Your task is to replace the blank (______) with rjust, ljust or center.

Input Format

A single line containing the thickness value for the logo.

Constraints

The thickness must be an odd number.

Output Format

Output the desired logo.

Sample Input

Sample Output

    H    
   HHH   
  HHHHH  
 HHHHHHH 
HHHHHHHHH
  HHHHH               HHHHH             
  HHHHH               HHHHH             
  HHHHH               HHHHH             
  HHHHH               HHHHH             
  HHHHH               HHHHH             
  HHHHH               HHHHH             
  HHHHHHHHHHHHHHHHHHHHHHHHH   
  HHHHHHHHHHHHHHHHHHHHHHHHH   
  HHHHHHHHHHHHHHHHHHHHHHHHH   
  HHHHH               HHHHH             
  HHHHH               HHHHH             
  HHHHH               HHHHH             
  HHHHH               HHHHH             
  HHHHH               HHHHH             
  HHHHH               HHHHH             
                    HHHHHHHHH 
                     HHHHHHH  
                      HHHHH   
                       HHH    
                        H

My Answer

#Replace all ______ with rjust, ljust or center.

thickness = int(raw_input()) #This must be an odd number
c = 'H'

#Top Cone
for i in range(thickness):
    print (c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1)

#Top Pillars
for i in range(thickness+1):
    print (c*thickness).center(thickness*2)+(c*thickness).center(thickness*6)

#Middle Belt
for i in range((thickness+1)/2):
    print (c*thickness*5).center(thickness*6)

# #Bottom Pillars
for i in range(thickness+1):
    print (c*thickness).center(thickness*2)+(c*thickness).center(thickness*6)

# #Bottom Cone
for i in range(thickness):
    print ((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6)