HDU 5326 Work(并查集)

本文提供了一个C语言程序,用于解决公司内部特定管理结构的问题。通过输入公司的员工数量及上下级关系,程序能计算出有多少员工直接或间接管理了指定数量的下属。

转载地址:http://blog.youkuaiyun.com/mengxiang000000/article/details/50570416

代码:

#include<stdio.h>
#include<string.h>
using namespace std;
int fa[105];
int num[105];
int n,k;
void init()
{
    memset(num,0,sizeof(num));
    for(int i=1;i<=n;i++)   fa[i]=i;
}
int findfa(int u)
{
    while(u!=fa[u])
    {
        num[fa[u]]++;
        u=fa[u];
    }
}
int main()
{
    while(~scanf("%d%d",&n,&k))
    {
        init();
        for(int i=0;i<n-1;i++)
        {
            int x,y;    scanf("%d%d",&x,&y);
            fa[y]=x;
        }
        for(int i=1;i<=n;i++)
        {
            findfa(i);
        }
        int ans=0;
        for(int i=1;i<=n;i++)
        {
            if(num[i]==k)
                ans++;
        }
        printf("%d\n",ans);
    }
}

 Work
Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u

Description



It’s an interesting experience to move from ICPC to work, end my college life and start a brand new journey in company. 
As is known to all, every stuff in a company has a title, everyone except the boss has a direct leader, and all the relationship forms a tree. If A’s title is higher than B(A is the direct or indirect leader of B), we call it A manages B. 
Now, give you the relation of a company, can you calculate how many people manage k people. 
 

Input

There are multiple test cases. 
Each test case begins with two integers n and k, n indicates the number of stuff of the company. 
Each of the following n-1 lines has two integers A and B, means A is the direct leader of B. 

1 <= n <= 100 , 0 <= k < n 
1 <= A, B <= n 
 

Output

For each test case, output the answer as described above.
 

Sample Input

     
7 2 1 2 1 3 2 4 2 5 3 6 3 7
 

Sample Output

     
2

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值