import java.awt.Point;
import java.util.HashSet;
import java.util.Set;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
Point[] points = new Point[5];
points[0] = new Point(-4, -4);
points[1] = new Point(-8, -582);
points[2] = new Point(-3, 3);
points[3] = new Point(-9, -651);
points[4] = new Point(9, 591);
System.out.println(maxPoints(points));
in.close();
}
public static int maxPoints(Point[] points) {
if (points == null)
return 0;
if (points.length < 1)
return 0;
if (points.length == 1)
return 1;
if (points.length == 2)
return 2;
//使用hashset 来保存已经处理过的直线的斜率
Set<Float> set = new HashSet<>();
Point initPoint;
int maxCount = 2;
//选取两个初始点来构建一条直线 用到了两重循环,循环中 识别已经处理过的直线,避免重复
for (int i = 0; i < points.length - 1; i++) {
initPoint = points[i];
for (int j = i + 1; j < points.length; j++) {
寻找平面内共线点数最多的直线和点数
最新推荐文章于 2024-07-27 10:30:00 发布