sum of all integer numbers

最新推荐文章于 2023-03-27 23:06:56 发布

原创最新推荐文章于 2023-03-27 23:06:56 发布 · 662 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#sum of all integer n

本文介绍了一个简单的编程任务：计算从1到给定整数N（包含）的所有整数的总和。该任务通过一个Java程序实现，程序接受用户输入的整数N，并输出1到N之间的所有整数的累加结果。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

sum of all integer numbers

时间限制：1000 ms | 内存限制：65535 KB

难度：0

描述

Your task is to find the sum of all integer numbers lying between 1 and N inclusive.

输入

There are multiple test cases.
The input consists of a single integer N that is not greater than 10000 by it's absolute value.

输出

Write a single integer number that is the sum of all integer numbers lying between 1 and N inclusive.

样例输入

样例输出

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner scanner = new Scanner(System.in);
		while (scanner.hasNext()) {
			int start = scanner.nextInt();
			int end = 1;
			int count = 0;
			// start有可能是比1小的数
			if (start > end) {
				int temp = start;
				start = end;
				end = temp;
			}
			for (int i = start; i <= end; i++) {
				count += i;
			}
			System.out.println(count);
		}
	}

}