Raymond于2019.12.09晚。
题目描述
给定一个二叉树,返回它的 前序 遍历。
示例:
输入: [1,null,2,3]
输出: [1,2,3]
进阶: 递归算法很简单,你可以通过迭代算法完成吗?
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/binary-tree-preorder-traversal
代码
1.递归实现
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
List<Integer> res = new ArrayList<>();
public List<Integer> preorderTraversal(TreeNode root) {
if ( root != null){
res.add(root.val);
preorderTraversal(root.left);
preorderTraversal(root.right);
}
return res;
}
}
2.迭代实现
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public List<Integer> preorderTraversal(TreeNode root) {
List<Integer> list = new ArrayList<>();
Stack<TreeNode> stack = new Stack<>();
if (root == null) return list;
stack.push(root);
while( !stack.isEmpty()){
TreeNode tmp = stack.pop();
list.add(tmp.val);
if (tmp.right != null){
stack.push(tmp.right);
}
if (tmp.left != null){
stack.push(tmp.left);
}
}
return list;
}
}