75. Sort Colors

本文介绍了一种解决数组中不同颜色对象排序问题的方法,通过计数每种颜色的对象数量,并将它们按顺序放置,实现颜色相邻且有序的排列。此算法不依赖于标准库提供的排序功能。

Given an array with n objects colored red, white or blue, sort them so that objects of the same color are adjacent, with the colors in the order red, white and blue.

Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.

Note:
You are not suppose to use the library's sort function for this problem.

click to show follow up.

Follow up:
A rather straight forward solution is a two-pass algorithm using counting sort.
First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's.

Could you come up with an one-pass algorithm using only constant space?

【思路】分别计算0,1,2的个数

class Solution {
public:
    void sortColors(vector<int>& nums) {
       int count_r = 0, count_w = 0, count_b = 0;
       vector<int>result;
       for(int i = 0; i < nums.size(); i++)
       {
           if(nums[i]==0)
            count_r++;
          if(nums[i]==1)
           count_w ++;
           if(nums[i]==2)
            count_b++;
       }
       
       for(int j = 0; j< count_r; j++)
       {
           result.push_back(0);
       }
       for(int k =0; k < count_w; k++)
       {
           result.push_back(1);
       }
        for(int w =0; w < count_b; w++)
       {
           result.push_back(2);
       }
       nums = result;
    }
};


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