求连续操作(登录)数量(次数)最大的记录(用户)
求登录时长
### DATEDIFF(d,LoginTime,getdate()) as diffDate ,
计算登录次数,登录时间为顺序来计算rownumber
### ROW_NUMBER() over(partition by Name order by LoginTime desc) as rn
合并起来
select top 1
Name,diffRn,COUNT(diffRn)as LoginCount
from(
select Name,diffDat.
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2020-07-07 00:57:39 ·
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