Given a string s and a number n, find the most frequently occurring n-gram in the string, where the n-grams can begin at any point in the string. This comes up in DNA analysis, where the 3-base reading frame for a codon can begin at any point in the sequence.
So for
s = 'AACTGAACG'
and
n = 3
we get the following n-grams (trigrams):
AAC, ACT, CTG, TGA, GAA, AAC, ACG
Since AAC appears twice, then the answer, hifreq, is AAC. There will always be exactly one highest frequency n-gram.