function commonParentNode(oNode1, oNode2) {
for(;oNode1;oNode1=oNode1.parentNode)
{
if(oNode1.contains(oNode2))
{
return oNode1;
}
}
}
dom节点查找
最新推荐文章于 2024-06-25 17:54:49 发布
function commonParentNode(oNode1, oNode2) {
for(;oNode1;oNode1=oNode1.parentNode)
{
if(oNode1.contains(oNode2))
{
return oNode1;
}
}
}