请实现 copyRandomList 函数,复制一个复杂链表。在复杂链表中,每个节点除了有一个 next 指针指向下一个节点,还有一个 random 指针指向链表中的任意节点或者 null。
示例 1:
输入:head = [[7,null],[13,0],[11,4],[10,2],[1,0]]
输出:[[7,null],[13,0],[11,4],[10,2],[1,0]]
示例 2:
输入:head = [[1,1],[2,1]]
输出:[[1,1],[2,1]]
示例 3:
输入:head = [[3,null],[3,0],[3,null]]
输出:[[3,null],[3,0],[3,null]]
示例 4:
输入:head = []
输出:[]
解释:给定的链表为空(空指针),因此返回 null。
提示:
-10000 <= Node.val <= 10000
Node.random 为空(null)或指向链表中的节点。
节点数目不超过 1000 。
理解题意:链表的深拷贝
HASH法:时间O(N),空间O(N)
"""
# Definition for a Node.
class Node:
def __init__(self, x: int, next: 'Node' = None, random: 'Node' = None):
self.val = int(x)
self.next = next
self.random = random
"""
class Solution:
def copyRandomList(self, head: 'Node') -> 'Node':
if head == None:
return None
org = []
res = []
new_head = Node(head.val)
org.append(head)
res.append(new_head)
head = head.next
while head != None:
new = Node(head.val)
org.append(head)
res.append(new)
head = head.next
for i in range(len(org)):
if org[i].next != None:
res[i].next = res[org.index(org[i].next)]
else:
res[i].next = None
if org[i].random != None:
res[i].random = res[org.index(org[i].random)]
else:
res[i].random = None
return new_head
不适用额外空间,在原链表添加节点 时间O(N),空间0(1)
"""
# Definition for a Node.
class Node:
def __init__(self, x: int, next: 'Node' = None, random: 'Node' = None):
self.val = int(x)
self.next = next
self.random = random
"""
class Solution:
def copyRandomList(self, head: 'Node') -> 'Node':
if head == None:
return None
cur = head
while cur != None: # 添加新节点
new = Node(cur.val)
new.next = cur.next
cur.next = new
cur = new.next
cur = head
while cur: # 设置random
cur.next.random = cur.random.next if cur.random else None
cur = cur.next.next
new_head = cur = head.next
while cur: # 去除新链表
cur.next = cur.next.next if cur.next else None
cur = cur.next
return new_head