hdu 1002 A + B Problem II(Java大数)-优快云博客

本文链接：https://blog.youkuaiyun.com/qq_24451605/article/details/44753895

本文介绍了一道名为“A+B Problem II”的编程题，该题要求输入两个大整数并计算其和。通过使用Java的BigInteger类，可以轻松解决大整数运算的问题。文章提供了完整的代码实现，展示了如何读取输入、计算和输出结果。

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A + B Problem II

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 244756 Accepted Submission(s): 47195

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input

2
1 2
112233445566778899 998877665544332211

Sample Output

Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

题目分析：　java随便秒

package hdu;

import java.util.Scanner;
import java.math.BigInteger;

public class Main {
		public static void main ( String args[] )
		{
			int t;
			Scanner cin = new Scanner ( System.in );
			t = cin.nextInt();
			int c = 1;
			while ( t-- != 0 )
			{
				BigInteger a = cin.nextBigInteger();
				BigInteger b = cin.nextBigInteger();
				System.out.println( "Case " + c++ + ":" );
				System.out.println ( a + " + " + b + " = " + a.add(b) );
				if ( t != 0 ) System.out.println ("");
			}
			cin.close();
		}
}