hdu2057 A + B Again

最新推荐文章于 2024-07-21 10:00:00 发布

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本文介绍了一个简单的十六进制加法程序实现方法，通过使用C++语言进行编程，能够处理多个测试用例中两个十六进制整数的加法运算，并输出其十六进制形式的结果。

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思路：模拟一个十六进制的加法，直接用scanf处理一下就好了

#include<iostream>
#include<algorithm>
#include<cstdio>
using namespace std;
#define LL long long
int main()
{
    LL a,b;
	while(scanf("%I64X%I64X",&a,&b)!=EOF)
	{
	    LL c = a+b;
		if (c<0)
		{
		    printf("-");
			c = -c;
		}
		printf("%I64X\n",c);
	}
}

A + B Again

Time Limit: 1000MS

Memory Limit: 32768KB

64bit IO Format: %I64d & %I64u

Submit Status

Description

There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

Input

The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

Output

For each test case,print the sum of A and B in hexadecimal in one line.

Sample Input

    
     
         
         +A -A
+1A 12
1A -9
-1A -12
1A -AA

Sample Output