Description
A Ducci sequence is a sequence of n-tuples of integers. Given an
n-tuple of integers (a1,
a2, ... , an), the next
n-tuple in the sequence is formed by taking the absolute differences of neighboring integers:
(a1, a2, ...
, an)
(|
a1 - a2|,| a2 - a3|, ...
,| an - a1|)
Ducci sequences either reach a tuple of zeros or fall into a periodic loop. For example, the 4-tuple sequence starting with 8,11,2,7 takes 5 steps to reach the zeros tuple:

(8, 11, 2, 7)
(3, 9, 5, 1)
(6, 4, 4, 2)
(2, 0, 2, 4)
(2, 2, 2, 2)
(0, 0, 0, 0).
The 5-tuple sequence starting with 4,2,0,2,0 enters a loop after 2 steps:





(4, 2, 0, 2, 0)
(2, 2, 2, 2, 4)
(0, 0, 0, 2, 2)
(0, 0, 2, 0, 2)
(0, 2, 2, 2, 2)
(2, 0, 0, 0, 2)







(2, 0, 0, 2, 0)
(2, 0, 2, 2, 2)
(2, 2, 0, 0, 0)
(0, 2, 0, 0, 2)
(2, 2, 0, 2, 2)
(0, 2, 2, 0, 0)







(2, 0, 2, 0, 0)
(2, 2, 2, 0, 2)
(0, 0, 2, 2, 0)
(0, 2, 0, 2, 0)
(2, 2, 2, 2, 0)
(0, 0, 0, 2, 2)
...
Given an n-tuple of integers, write a program to decide if the sequence is reaching to a zeros tuple or a periodic loop.





Input
Your program is to read the input from standard input. The input consists of
T test cases. The number of test cases
T is given in the first line of the input. Each test case starts with a line containing an integer
n (3
n
15),
which represents the size of a tuple in the Ducci sequences. In the following line,
n integers are given which represents the
n-tuple of integers. The range of integers are from 0 to 1,000. You may assume that the maximum number of steps of a Ducci sequence reaching zeros tuple or making a loop does not exceed 1,000.


Output
Your program is to write to standard output. Print exactly one line for each test case. Print `LOOP' if the Ducci sequence falls into a periodic loop, print `ZERO' if the Ducci sequence reaches to a zeros tuple.The following
shows sample input and output for four test cases.
Sample Input 
4 4 8 11 2 7 5 4 2 0 2 0 7 0 0 0 0 0 0 0 6 1 2 3 1 2 3
Sample Output
ZERO LOOP ZERO LOOP
分析:每组数据就是一组元,放在一个vector中,保存每次的状态,判断是否为0,判断map中是否存在当前状态。
#include <iostream>
#include <map>
#include <vector>
#include <cmath>
using namespace std;
vector<int> pairs;
map<vector<int>,int> pairbuf;
int iszero()
{
for(int i=0; i<pairs.size(); i++)
if(pairs[i])return 0;
return 1;
}
int main()
{
int T;
cin >> T;
while(T--)
{
int n;
cin >> n;
pairs.clear(); pairbuf.clear();
for(int i=0; i<n; i++)
{
int x;
cin >> x;
pairs.push_back(x);
}
int rnd = 0;
while(1)
{
int z0 = pairs[0];
for(int i=0; i<n-1; i++)
{
pairs[i]=abs(pairs[i]-pairs[i+1]);
}
pairs[n-1]=abs(pairs[n-1]-z0);
if(iszero()){cout << "ZERO" << endl;break;}
if(pairbuf.count(pairs)){cout << "LOOP" << endl; break;}
pairbuf[pairs] = rnd;
rnd++;
}
}
return 0;
}