写一个功能函数实现从数组中找出两个值相加等于某一个值，要求时间复杂度为 n;

#include <iostream>

using namespace std;

void Func(int array[], int length,int thenumber,  int &num1,  int &num2)

{

       int head = 0;

       int tail = length - 1;

       while (head != tail)

       {

              int temp = array[head] + array[tail];

              if (temp == thenumber)

              {

                     num1 = array[head];

                     num2 = array[tail];

                     cout << num1 <<'\t'<< num2<<endl;

                     head++;

                     tail--;

                     continue;

              }

              if (temp > thenumber)

                     tail--;

              else

                     head++;

       }

}

int main()

{

       int abc[] = { 0,1,3,5,6,8,9,11,12,13,14,15,16 };

       int length = sizeof(abc) / sizeof(abc[0]);

       int a, b;

       Func(abc, length,15, a, b);

       getchar();

    return 0;

}