航电oj1201 （18岁生日） 水题记录

航电oj1201 AC代码

using namespace std;
#include<iostream>
bool leapyear(int x)
{
	if((x%4 == 0&&x%100 != 0)||(x%100 == 0&&x%400 == 0))
           return true;
		   else 
		   return false;	
}
int getyear(char *a)
{    int year=0;
	for(int i=0;i<=3;i++)
	{
		year*=10;
		year=year+int(a[i]-48);
	}
	return year;
}
int main()
{
	int T,sum_day = 6570,year1=0,year2=0;
	char borndate[11];
	cin>>T;
	while(T--)
	{   
	    int addday=0;
		cin>>borndate;
		year1 = getyear(borndate);
		year2 = year1+18;
		 if(borndate[5]=='0'&&borndate[6]=='2'&&borndate[8]=='2'&&borndate[9]=='9')
		{
				cout<<"-1"<<endl;
			
		}
		else if(leapyear(year1)==false&&leapyear(year2) == false)
		 {
		 	for(int i=year1+1;i<year2;i++)
		 	if(leapyear(i))
		 	  addday++;
		 	cout<<sum_day+addday<<endl;
		 }
		
	    else if(leapyear(year1)==true&&leapyear(year2)==false)
	         {
	         	 for(int i=year1+1;i<year2;i++)
				if(leapyear(i))
		 	      addday++;
		 	      if(borndate[6]>='3'||borndate[5]>'0')
		 	   cout<<sum_day+addday<<endl;
		 	   if(borndate[6]<'3'&&borndate[5] == '0')
		 	   cout<<sum_day+addday+1<<endl;
			 }
		else if(leapyear(year1)==false&&leapyear(year2)==true)
	         {
	         	 for(int i=year1+1;i<year2;i++)
				if(leapyear(i))
		 	      addday++;
		 	      if(borndate[6]>='3'||borndate[5]>'0')
		 	   cout<<sum_day+addday+1<<endl;
		 	   if(borndate[6]<'3'&&borndate[5] == '0')
		 	   cout<<sum_day+addday<<endl;
			 }
		
	}
	return 0;
	}

出生年为闰年，生日一定不为闰年，判断首尾年的情况，以及出生年在2.29的前后，即可得到到18岁生日经历的天数。