Codeforces Round #317 (Div. 2) 572A.Arrays

解题报告：Codeforces Round #317 Editorial

A. Arrays

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

You are given two arrays A and B consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose knumbers in array A and choose m numbers in array B so that any number chosen in the first array is strictly less than any number chosen in the second array.

Input

The first line contains two integers nA, nB (1 ≤ nA, nB ≤ 105), separated by a space — the sizes of arrays A and B, correspondingly.

The second line contains two integers k and m (1 ≤ k ≤ nA, 1 ≤ m ≤ nB), separated by a space.

The third line contains nA numbers a1, a2, ... anA ( - 109 ≤ a1 ≤ a2 ≤ ... ≤ anA ≤ 109), separated by spaces — elements of array A.

The fourth line contains nB integers b1, b2, ... bnB ( - 109 ≤ b1 ≤ b2 ≤ ... ≤ bnB ≤ 109), separated by spaces — elements of array B.

Output

Print "YES" (without the quotes), if you can choose k numbers in array A and m numbers in array B so that any number chosen in arrayA was strictly less than any number chosen in array B. Otherwise, print "NO" (without the quotes).

Sample test(s)

input

3 3
2 1
1 2 3
3 4 5

output

YES

input

3 3
3 3
1 2 3
3 4 5

output

NO

input

5 2
3 1
1 1 1 1 1
2 2

output

YES

Note

In the first sample test you can, for example, choose numbers 1 and 2 from array A and number 3 from array B (1 < 3 and 2 < 3).

In the second sample test the only way to choose k elements in the first array and m elements in the second one is to choose all numbers in both arrays, but then not all the numbers chosen in A will be less than all the numbers chosen in B: .

分析：因为a[]和b[]是有序的只要比较是否a[k-1]<b[M-m]

#include
  
   
#include
   
    
#include
    
     
#include
     
      
using namespace std;
const int maxn=100002;
int a[maxn],b[maxn];
int main(void)
{
    int m,i,k,M,N;
    while(~scanf("%d%d",&N,&M))
    {
        scanf("%d%d",&k,&m);
        for(i=0;i