C# 调用Web Api post提交json格式_c# webapi 发送json-优快云博客

本文展示了一个使用C#向WebApi发起POST请求并发送JSON格式数据的示例。通过设置HTTP请求头和内容类型，该示例演示了如何构造请求、发送数据，并接收来自服务器的响应。

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C# 调用Web Api post提交json格式

    public static void sdf(string urls) 
    {
        string url = urls;
        //定义request并设置request的路径
        WebRequest request = WebRequest.Create(url);
        request.Method = "post";
        //初始化request参数
        string postData = "{\"dataSource\":\"DataSource=192.168.0.70/orcl70;UserID=sde;PassWord=sde;\",\"type\":\"0\",\"whereCondition\":\"dlwz='国和百寿一村6号'\",\"tableName\":\"hzdzd_pt\"}";
        //var json = "{ \"dataSource\": \"Data Source=(DESCRIPTION=(ADDRESS=(PROTOCOL=TCP)(HOST=192.168.0.70)(PORT=1521))(CONNECT_DATA=(SERVICE_NAME=orcl70)));User ID=sde;Password=sde;Unicode=True\" }";
        //设置参数的编码格式，解决中文乱码
        byte[] byteArray = Encoding.UTF8.GetBytes(postData);
        //设置request的MIME类型及内容长度
        request.ContentType = "application/json";
        request.ContentLength = byteArray.Length;
        //打开request字符流
        Stream dataStream = request.GetRequestStream();
        dataStream.Write(byteArray, 0, byteArray.Length);
        dataStream.Close();
        //定义response为前面的request响应
        WebResponse response = request.GetResponse();
        //获取相应的状态代码
        Console.WriteLine(((HttpWebResponse)response).StatusDescription);
        //定义response字符流
        dataStream = response.GetResponseStream();
        StreamReader reader = new StreamReader(dataStream);
        string responseFromServer = reader.ReadToEnd();//读取所有
        Console.WriteLine(responseFromServer);
    }