10.1 第一天打卡

In this kata you are required to, given a string, replace every letter with its position in the alphabet.

If anything in the text isn't a letter, ignore it and don't return it.

def alphabet_position(text):
    number = []
    alphabets = list(text.lower())
    for alphabet in alphabets:
        if ord(alphabet) > 97 and ord(alphabet) < 122:
           number.append(ord(alphabet)-96)
        else:
            pass;
    number_2 = [str(i) for i in number]
    return " ".join(number_2)

还在考虑哪里错了。

附高分参考答案

def alphabet_position(text):
    alphabet = 'abcdefghijklmnopqrstuvwxyz'
    return ' '.join(str(alphabet.index(x) + 1) for x in text.lower() if x.isalpha())