Implement strStr().
Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
Update (2014-11-02):
The signature of the function had been updated to return the index instead of the pointer. If you still see your function signature returns a char
* or String, please click the reload button to
reset your code definition.
还是Easy Mode.直接上代码
public class Solution {
public int strStr(String haystack, String needle) {
if(needle.length()>haystack.length())return -1;
if(needle.length()==0)return 0;
for(int i=0;i<=haystack.length()-needle.length();i++){
int j=0;
while(haystack.charAt(i+j)==needle.charAt(j)){
if(j==needle.length()-1)return i;
j++;
}
//i=i+j;
}
return -1;
}
}本想通过i=i+j进行剪枝减少重复,不过有点问题,懒的多想了,就这吧。
本文提供了一种实现strStr()函数的方法,该函数用于查找一个字符串(needle)在另一个字符串(haystack)中首次出现的位置,并返回其索引。若未找到则返回-1。文章附带了具体的Java代码实现。
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