58 Length of Last Word-优快云博客

本文介绍了一个C++程序，该程序能够处理包含大小写字母及空格的字符串，并返回最后一个单词的长度。通过istringstream读取字符串并去除尾部空白字符，然后定位到第一个非空格字符确定单词边界。

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Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = "Hello World",

return 5.

#include <iostream>
#include <sstream>
using namespace std;

//Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.
//
//If the last word does not exist, return 0.
//
//Note: A word is defined as a character sequence consists of non-space characters only.
//
//For example, 
//Given s = "Hello World",
//return 5.



class Solution {
public:
    int lengthOfLastWord(const char *s) {
        stringstream ss(s);
        string tem	;
		getline(ss,tem);
		int len = tem.length();
		int i;
		for(i = len -1 ; i >= 0;i--)
		{
			if(tem[i] != ' ')break;
		}
		len = i;
		for(;i >= 0; i--)
		{
			 if(tem[i] == ' ')break;
		}
		return len -i;


    }
};

int main()
{
	Solution s;
	char t[] = "Hello World";
	cout<<s.lengthOfLastWord(t)<<endl;
	getchar();
	
	return 0;
}