Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false.
Each letter in the magazine string can only be used once in your ransom note.
Note:
You may assume that both strings contain only lowercase letters.
canConstruct(“a”, “b”) -> false
canConstruct(“aa”, “ab”) -> false
canConstruct(“aa”, “aab”) -> true
class Solution {
public:
bool canConstruct(string ransomNote, string magazine) {
bool ret = true;
int pos = -1;
for(auto it : ransomNote) {
pos = magazine.find(it);
if(pos == string::npos) {
ret = false;
break;
}
else {
magazine.erase(magazine.begin() + pos);
}
}
return ret;
}
};
勒索信字符串匹配算法
本文介绍了一种检查是否能从杂志字符串中构建出勒索信字符串的算法。该算法通过遍历勒索信字符串,并在杂志字符串中查找每个字符是否存在且未被使用过。若所有字符都能找到,则返回true;反之则返回false。此方法确保了杂志中的每个字母只能在勒索信中使用一次。
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