[每日练习]十进制数转换为n进制数

static char *Dec2N(int num, int n)
{
 static char hexBuf[sizeof(int)*8+1];
 unsigned int c;
 int i = 0;
 char *begin, *end, tmp;
 
 while (num!=0)
 {
  c = num%n;
  hexBuf[i++] = c>9?c+'a'-10:c+'0';
  num /= n;
 }
 hexBuf[i] = '\0';
 
 printf("end\n");
 
 begin = &hexBuf[0];
 end = &hexBuf[i-1];
 
 while(begin < end)
 {
  tmp = *begin;
  *begin = *end;
  *end = tmp;
  begin++;
  end--;
 }
 return hexBuf;
}