mysql的另一种迭代查询方式

 

USE acexeym_packcode;

DROP PROCEDURE IF EXISTS UP_Code_GetByParentCode_test;

CREATE PROCEDURE `UP_Code_GetByParentCode_test`(IN _Code nvarchar(100),
IN _Layer int,
IN _CompanyId bigint)
BEGIN
  DECLARE _sql varchar(4000);
  DECLARE _codes varchar(4000);
  DECLARE _count,roundcount,_lastcodelength int;
  SET _count=1,roundcount=0,_lastcodelength=0;
  SET _codes=CONCAT('''',_Code,'''');


  read_while:
  WHILE  _count>0 DO 
    SET  roundcount=roundcount+1;
    IF roundcount>5 THEN  
        LEAVE read_while;
    END IF;  
    SET @a='',@b='';      
    SET _sql= CONCAT('SELECT title INTO @b FROM (','select  @a:=CONCAT(@a,'','''''',packcode,'''''''') AS title from code_',
    _CompanyId,' WHERE parentcode in(',_codes,') and companyid=? )a ORDER BY title DESC  LIMIT 1');
    SET @sql=_sql;
    SET @companyid=_CompanyId;
    PREPARE sqlstr FROM @sql;
    EXECUTE sqlstr USING @companyid;
   
    IF _lastcodelength=LENGTH(@b) THEN
      SET _count=0;
      LEAVE read_while;
    END IF;
    SET _lastcodelength= LENGTH(@b);

    IF(length(@b)>3) THEN
      if length(@b)>3 THEN
         SET _codes =CONCAT(_codes,',', SUBSTRING(@b,2));
      ELSE  
         SET _codes =SUBSTRING(@b,2);
      END IF;
    ELSE
      LEAVE read_while;
    END IF;
  END WHILE;
 
  SET _sql=CONCAT('SELECT  * FROM code_',_CompanyId,'  WHERE parentcode in(',_codes,') and companyid=?');
  SET @sql=_sql;
  SET @companyid=_CompanyId;
  PREPARE sqlstr FROM @sql;
  EXECUTE sqlstr USING @companyid;
  DEALLOCATE PREPARE sqlstr;

END

 

数据库迭代查询作业 emp(eno, ename, salary, mgr),其中mgr是员工领导,设计约束:要求领导的工资不能低于他的下属平均工资。(注意,这是一个递归查询) 下面是一些样例数据 CREATE TABLE dbo.Employees ( empid INT NOT NULL PRIMARY KEY, mgrid INT NULL REFERENCES dbo.Employees, empname VARCHAR(25) NOT NULL, salary MONEY NOT NULL, CHECK (empid mgrid) ); INSERT INTO dbo.Employees(empid, mgrid, empname, salary) VALUES(1, NULL, 'David', $10000.00); INSERT INTO dbo.Employees(empid, mgrid, empname, salary) VALUES(2, 1, 'Eitan', $7000.00); INSERT INTO dbo.Employees(empid, mgrid, empname, salary) VALUES(3, 1, 'Ina', $7500.00); INSERT INTO dbo.Employees(empid, mgrid, empname, salary) VALUES(4, 2, 'Seraph', $5000.00); INSERT INTO dbo.Employees(empid, mgrid, empname, salary) VALUES(5, 2, 'Jiru', $5500.00); INSERT INTO dbo.Employees(empid, mgrid, empname, salary) VALUES(6, 2, 'Steve', $4500.00); INSERT INTO dbo.Employees(empid, mgrid, empname, salary) VALUES(7, 3, 'Aaron', $5000.00); INSERT INTO dbo.Employees(empid, mgrid, empname, salary) VALUES(8, 5, 'Lilach', $3500.00); INSERT INTO dbo.Employees(empid, mgrid, empname, salary) VALUES(9, 7, 'Rita', $3000.00); INSERT INTO dbo.Employees(empid, mgrid, empname, salary) VALUES(10, 5, 'Sean', $3000.00); INSERT INTO dbo.Employees(empid, mgrid, empname, salary) VALUES(11, 7, 'Gabriel', $3000.00); INSERT INTO dbo.Employees(empid, mgrid, empname, salary) VALUES(12, 9, 'Emilia' , $2000.00); INSERT INTO dbo.Employees(empid, mgrid, empname, salary) VALUES(13, 9, 'Michael', $2000.00); INSERT INTO dbo.Employees(empid, mgrid, empname, salary) VALUES(14, 9, 'Didi', $1500.00);
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