注意题目给出的式子:
n1 = n3 = max { k| k <= n2 for all 3 <= n2 <= N } with n1 + n2 + n3 - 2 = N.
因为取n1,n3得最大值,所以当k=n2时,n1,n3为最大值。
得到n1=n3=(N+2)/3;
且n2=N+2-(n1+n3);
注意题目给出的式子:
n1 = n3 = max { k| k <= n2 for all 3 <= n2 <= N } with n1 + n2 + n3 - 2 = N.
因为取n1,n3得最大值,所以当k=n2时,n1,n3为最大值。
得到n1=n3=(N+2)/3;
且n2=N+2-(n1+n3);