一些pythonic的代码

最新推荐文章于 2025-07-14 23:37:00 发布

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本文介绍了一种Pythonic的方法，将二维列表转换为一维列表并对相同位置的元素进行求和。通过使用内置函数`zip()`配合列表推导式及`sum()`函数实现这一目标。

I'm pretty sure there should be a more Pythonic way of doing this - but I can't think of one: How can I merge a two-dimensional list into a one-dimensional list? Sort of like zip/map but with more than two iterators.

Example - I have the following list:

array = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]

I want to have

result = [12, 15, 18] # [1+4+7, 2+5+8, 3+6+9]use：
[sum(a) for a in zip(*array)]57down
 vote [sum(value)
 for value in zip(*array)] is pretty standard.
This
 might help you understand it:
In [1]: array=[[1, 2, 3], [4, 5, 6], [7, 8, 9]]

In [2]: array
Out[2]: [[1, 2, 3], [4, 5, 6], [7, 8, 9]]

In [3]: *array
------------------------------------------------------------
   File "<ipython console>", line 1
     *array
     ^
<type 'exceptions.SyntaxError'>: invalid syntax
The
 unary star is not an operator by itself. It unwraps array elements into arguments into function calls.
In [4]: zip(*array)
Out[4]: [(1, 4, 7), (2, 5, 8), (3, 6, 9)]
zip()
 is a built-in function
In [5]: zip(*array)[0]
Out[5]: (1, 4, 7)
each
 element for the list returned by zip is a set of numbers you want.
In [6]: sum(zip(*array)[0])
Out[6]: 12

In [7]: [sum(values) for values in zip(*array)]
Out[7]: [12, 15, 18]