Introduction to Java Programming编程题3.22<判断点是否在矩形内>

最新推荐文章于 2023-04-19 22:36:28 发布

Okwarry

最新推荐文章于 2023-04-19 22:36:28 发布

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分类专栏： Java 文章标签： java

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本文介绍了一个简单的Java程序，用于判断一个二维坐标点是否位于指定的矩形区域内。通过用户输入坐标值，程序能够即时反馈该点是否落在定义好的矩形内。

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/*
Enter a point with two coordinates: 2 7
Point (2.0, 7.0) is not in the rectangle.

Enter a point with two coordinates: 2 2
Point (2.0, 2.0) is in the rectangle.
*/
import java.util.Scanner;

public class PointInARectagle {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        double x1 = 10 / 2, y1 = 5 / 2;

        System.out.print("Enter a point with two coordinates: ");
        double x2 = input.nextDouble();
        double y2 = input.nextDouble();

        if (x2 <= x1 && y2 <= y1)
            System.out.println("Point (" + x2 + ", " + y2 + ")" + " is in the rectangle.");
        else
            System.out.println("Point (" + x2 + ", " + y2 + ")" + " is not in the rectangle.");
    }
}