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NYNU_ACM
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夹角有多大(题目已修改,注意读题)
夹角有多大(题目已修改,注意读题)Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 9312 Accepted Submission(s): 3719Problem Description时间过的好快，一个学期就原创 2014-10-10 09:01:58 · 845 阅读 · 0 评论 -
杭电oj find your present (2)
我之前写的是Memory Limit Exceeded，但是感觉方法很对，运行结果也很正确。原创 2014-10-01 09:14:02 · 943 阅读 · 0 评论 -
人见人爱A-B
#include#include#includeusing namespace std;int main(){ int n,m,i,j; while(scanf("%d%d",&n,&m),n||m) { int a[100]; int b[100]; int c[100]; int k=0;原创 2014-10-01 23:01:35 · 1215 阅读 · 0 评论 -
蟠桃记
蟠桃记Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 35019 Accepted Submission(s): 26388Problem Description喜欢西游记的同学肯定都知道悟空偷吃蟠桃的故事，你原创 2014-10-01 13:49:23 · 776 阅读 · 0 评论 -
杭电oj A + B Again
A + B AgainTime Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 15358 Accepted Submission(s): 6700Problem DescriptionThere must be man原创 2014-10-02 19:51:27 · 1015 阅读 · 0 评论 -
Lowest Common Multiple Plus
Lowest Common Multiple PlusTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 33483 Accepted Submission(s): 13687Problem Description原创 2014-10-03 17:06:44 · 734 阅读 · 0 评论 -
杭电oj An easy problem
#include#includeusing namespace std;int main(){ int T,i; char x; double y,sum; cin>>T; while(T--) { cin>>x>>y; if(x>='A'&&x<='Z') { for(i=0;i<26;i++) { if(x=='A'+i) {原创 2014-10-02 19:36:22 · 1006 阅读 · 0 评论 -
大二英语单词（粗略）
stability n.稳定corruption 腐败eliminate(消灭 除掉 淘汰 排除)/ fight against corruptiongeilivable adj. 给力的canteen 食堂，水壶，餐具柜aggressive adj.进取的，激烈的，暴躁的，好斗的，凶猛的priority 优先考虑的事agrarian 农业的，土地的maintai原创 2014-09-29 14:05:49 · 1042 阅读 · 0 评论 -
Palindromes _easy version
Palindromes _easy versionTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 21769 Accepted Submission(s): 13576Problem Description“回原创 2014-10-04 17:34:11 · 1059 阅读 · 0 评论