Text Justification leetcode

Text Justification

Apr 3 '12

3100 / 15986

Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified.

You should pack your words in a greedy approach; that is, pack as many words as you can in each line. Pad extra spaces ' ' when necessary so that each line has exactly L characters.

Extra spaces between words should be distributed as evenly as possible. If the number of spaces on a line do not divide evenly between words, the empty slots on the left will be assigned more spaces than the slots on the right.

For the last line of text, it should be left justified and no extra space is inserted between words.

For example,
words: ["This", "is", "an", "example", "of", "text", "justification."]
L: 16.

Return the formatted lines as:

[

   "This    is    an",

   "example  of text",

   "justification.  "

]

Note: Each word is guaranteed not to exceed L in length.

，大体思路ok了，细节仍有错误

package String;  

import java.util.ArrayList;

/** 
 * @Title: Text_Just.java 
 * @Package String 
 * @Description: TODO
 * @author nutc
 * @date 2013-9-6 上午9:50:57 
 * @version V1.0 
 */
public class Text_Just {
	
	public static void main(String args[]){
		Text_Just t = new Text_Just();
		String[] s = {"a","b","c","d","e"};
		ArrayList<String> list = t.fullJustify(s, 3);
		System.out.println(list);
	}
	    public ArrayList<String> fullJustify(String[] words, int L) {


	        if(words==null||words.length==0) return null;
	        ArrayList<String> list = new ArrayList<String>();
	        
	        
	        int i=0,j=0,now = 0;
	        while(i<words.length){
	            j = i;
	            now = 0;
	            now += words[i].length();
	            while(++i<words.length && (words[i].length()+1+now)<=L){
	                now += words[i].length()+1;//保证两个
	            }
	            i--; //i  还是要剪掉的！
	            if(i==j){
	                StringBuilder sb = new StringBuilder(words[i]);
	                for(int k=1;k<=L-now;k++)
	                    sb.append(" ");
	                list.add(sb.toString());
	            }else{
	                int divide = (L-now+(i-j))/(i-j);
	                int add = (L-now+(i-j))%(i-j);
	                StringBuilder sb = new StringBuilder(words[j]);
	                for(int k = 1;k<=(divide+add);k++){
	                    sb.append(" ");
	                }
	                for(int k=j+1;k<i;k++){
	                    sb.append(words[k]);
	                    for(int m = 1;m<=divide;m++){
	                        sb.append(" ");
	                    }
	                }
	                sb.append(words[i]);
	                list.add(sb.toString());
	            }
	            i++;
	        }
	        return list;
	        
	    }
}