解析思路:利用层序遍历+队列来实现,一层一层的遍历
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public List<List<Integer>> levelOrder(TreeNode root) {
List<List<Integer>> res = new ArrayList<>();
if(root == null){
return res;
}
Queue<TreeNode> q = new LinkedList<>();
q.offer(root);
while(!q.isEmpty()){
int size = q.size();
List<Integer> list = new ArrayList<>();
for(int i = 0; i < size; i++){
TreeNode cur = q.poll();
list.add(cur.val);
if(cur.left != null){
q.offer(cur.left);
}
if(cur.right != null){
q.offer(cur.right);
}
}
res.add(list);
}
return res;
}
}

/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public int[] levelOrder(TreeNode root) {
if(root == null){
return new int[0];
}
List<Integer> res = new ArrayList<>();
Queue<TreeNode> q = new LinkedList<>();
q.offer(root);
while(!q.isEmpty()){
TreeNode cur = q.poll();
res.add(cur.val);
if(cur.left != null){
q.offer(cur.left);
}
if(cur.right != null){
q.offer(cur.right);
}
}
int[] ans = new int[res.size()];
for(int i = 0; i < res.size();i++){
ans[i] = res.get(i);
}
//int[] ans = res.stream().mapToInt(Integer::intValue).toArray();
return ans;
}
}
文章提供了两种使用Java实现二叉树层序遍历的方法。第一种返回层次节点值的列表列表,第二种返回层次节点值的整数数组。方法基于队列进行层次遍历,从根节点开始,逐层添加左右子节点到队列中,直到队列为空。

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