兴*数金的编程题之一

@兴*数金的编程题之一

题目

输入一个字符串，将字符串代表数字转换成二进制和十六进制字符串。
若输入字符串，不是合法数字则输出"INPUTERROR";
若输入字符串，超出int的范围则输出"NODATA"，int范围[-2¹⁵, 2¹⁵-1];
若二进制不足16位用0补足，若十六进制不足4位用0补足。

样例

输入:"15"
输出:"0000000000001111,000F"

输入:"-1"
输出:"1111111111111111,FFFF"

下流的答案

import java.util.*;

/**
 * @Author Hawkii
 * @Date 2020/12/24
 */


public class Solution {
    public static void main(String[] args) {
        Solution s = new Solution();
        System.out.println(s.changeFormatNumber0("**0"));
        System.out.println(s.changeFormatNumber0("-10000"));
        System.out.println(s.changeFormatNumber0("30"));
        System.out.println(s.changeFormatNumber0("15555555555"));
    }
    /**
     * 将输入的十进制数字转换为对应的二进制字符串和十六进制字符串
     * @param number string字符串 十进制数字字符串
     * @return string字符串
     */
    public String changeFormatNumber0 (String number) {
        char[] n = number.toCharArray();
        int len = number.length();
        int minus;
        if(n[len-1] == '-')
            minus = 1;
        else if(n[len-1] >= '0' && n[len-1] <= '9')
            minus = 0;
        else
            return "INPUTERROR";
        long sum=0;
        for(int i=0; i<=len-1; i++)
        {
            if(minus==1 && i==0)
                continue;
            if(n[i]>'9' || n[i]<'0')
                return "INPUTERROR";
            else
                sum = sum * 10 +n[i]-'0';
            if(sum > 0x80000000 && minus==1)
                return "NODATA";
            if(sum > 0x7FFFFFFF)
                return "NODATA";
        }
        int num=(int)sum;
        String str2="";
        String str16="";
        String index = "0123456789ABCDEF";
        char[] chars = index.toCharArray();
        for (int i=0; i<16; i++)
        {
            if(num % 2 == 0)
                str2 = "0" + str2;
            else
                str2 = "1" + str2;
            num = num>>1;
        }
        num=(int)sum;
        for (int i=0,j; i<4; i++)
        {
            j = num % 16;
            str16 = chars[j] + str16;
            num = num>>4;
        }
        return str2+","+str16;
    }
}

上流的答案

import java.util.*;

/**
 * @Author Hawkii
 * @Date 2020/12/24
 */


public class Solution {
    public static void main(String[] args) {
        Solution s = new Solution();
        System.out.println(s.changeFormatNumber1("**0"));
        System.out.println(s.changeFormatNumber1("-10000"));
        System.out.println(s.changeFormatNumber1("30"));
        System.out.println(s.changeFormatNumber1("15555555555"));
    }
    public String changeFormatNumber1 (String number) {
        String str2="";
        String str16="";
        char[] chars = number.toCharArray();
        //截取正数部分
        if(chars[0] == '-')
            chars = number.substring(1,number.length()).toCharArray();
        //遍历判断是否合法
        for(int i=0; i<chars.length; i++){
            if(chars[i]<'0' || chars[i]>'9')
                return "INPUTERROR";
        }
        try {
            long numL = Integer.parseInt(number);
            int num = (int) numL;
            str2 = Integer.toBinaryString(num);
            str16 = Integer.toHexString(num);
            str16 = str16.toUpperCase();
        }catch (NumberFormatException ne){
            return "NODATA";
        }
        while(str2.length()<16)
            str2 = "0" + str2;
        while(str16.length()<4)
            str16 = "0" + str16;
        return str2+","+str16;
    }
}