题目传送门: 【深基16.例3】二叉树深度
/*
Takes:luogu
Title:P4913
Time:2025/1/15
*/
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define endl '\n'
// #pragma GCC optimize(2)
#define pii pair<int, int>
#define pdd pair<double, double>
#define psi pair<string, int>
#define be(x) x.begin(), x.end()
#define fi first
#define se second
#define pb push_back
#define SZ(x) ((int)(x).size())
pii A[1000001];
int dfs(int c)
{
if (A[c].first == 0 && A[c].second == 0)
return 0;
return max(dfs(A[c].first), dfs(A[c].second)) + 1;
}
void solve()
{
int n;
cin >> n;
for (int i = 1; i <= n; i++)
cin >> A[i].first >> A[i].second;
cout << dfs(1) + 1 << endl;
}
int main()
{
ios::sync_with_stdio(false), cin.tie(0);
int t = 1;
// cin >> t;
while (t--)
solve();
return 0;
}