Codeforces Round #361 (Div. 2)-D 题解
因为
maxi=lra[i]−mini=lrb[i]<=maxi=lr+1a[i]−mini=lr+1b[i]\max_{i=l}^r a[i] -\min_{i=l}^r b[i] <= \max_{i=l}^{r+1} a[i] -\min_{i=l}^{r+1} b[i],可知当左端点l确定时,使
maxi=lra[i]=mini=lrb[i]\max_{i=l}^r a[i] =\min
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2016-07-07 12:10:41 ·
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