UVA 11991 Easy Problem from Rujia Liu?

本文介绍了一种使用C++中的map和vector数据结构来高效处理查询问题的方法。通过实例演示了如何根据输入数据构建映射关系,并针对特定查询返回结果。此方案能有效解决大数据集中的查找和定位问题。

用map 和vector很巧妙的解决了


#include<iostream>
#include<cstdio>
#include<map>
#include<vector>
using namespace std;
map <int, vector<int> > a;
int main()
{	
	int n,m;
	while(scanf("%d%d",&n,&m)!=EOF)
	{
		a.clear();
		int temp,k,v;
		for(int i=0;i<n;i++)
		{
				scanf("%d",&temp);
				a[temp].push_back(i+1);
		}
		while(m--)
		{
			scanf("%d%d",&k,&v);
			if(a[v].size()<k) printf("0\n");
			else printf("%d\n",a[v][k-1]);
		}
	}
}


请帮我写一份c++代码,解决一下问题,要求符合输入输出样本There are n people (excluding myself) in my 30th birthday party. They sing the traditional “happy birthday” song: Happy birthday to you! Happy birthday to you! Happy birthday to Rujia! Happy birthday to you!!! Since I love music, I want to hear something more interesting, not that everyone sings together. Ah yes, I want one person to sing one word! For example, there are three people: Mom, Dad, Girlfriend, I’d like them to sing like this: Mom: Happy Dad: birthday Girlfriend: to Mom: you Dad: Happy Girlfriend: birthday Mom: to Dad: you Girlfriend: Happy Mom: birthday Dad: to Girlfriend: Rujia Mom: Happy Dad: birthday Girlfriend: to Mom: you Very nice, right? What if there are more than 16 people? That’s easy: repeat the song until everyone has sung at least once :) Please, don’t stop in the middle of the song.Input There is only one test case. The first line contains a single integer n (1 ≤ n ≤ 100). Then each of the next n lines contains a capitalized name (i.e. one upper-case letter followed by zero or more lowercase letters). Each name contains at most 100 characters and do not have whitespace characters inside. Output Output the song, formatted as above. Sample Input 3 Mom Dad Girlfriend Sample Output Mom: Happy Dad: birthday Girlfriend: to Mom: you Dad: Happy Girlfriend: birthday Mom: to Dad: you Girlfriend: Happy Mom: birthday Dad: to Girlfriend: Rujia Mom: Happy Dad: birthday Girlfriend: to Mom: you
最新发布
12-06
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