原题:
Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4
and you are given the third node with value 3
, the linked list should become 1 -> 2 -> 4
after calling your function.
解决方法:
好像题意和给的函数定义出现了不匹配的情况。
无论如果,注意值和指针的赋值。
代码:
void deleteNode(ListNode* node) {
if (node && node->next){
node->val = node->next->val;
node->next =node->next->next;
}
}