【C语言】日期输出

berdeng

已于 2022-10-15 23:48:32 修改

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文章标签： c语言开发语言

于 2022-10-15 23:45:19 首次发布

本文链接：https://blog.youkuaiyun.com/mozi196/article/details/127342545

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C语言明日计算器

输入今天（today）日期可计算出第二天（tomorrow）日期。

#include<stdio.h>
#include<stdbool.h>
//声明结构体变量 
struct date{
	int month;
	int day;
	int year;
};

bool isLeap(struct date d);//判断是否闰年 
int numberOfDays(struct date d);// 

int main(int argc,char const *argv[])
{
	struct date today,tomorrow;
	
	printf("Enter today's date(mm dd yyyy):");
	scanf("%d %d %d",&today.month,&today.day,&today.year);
	
	if(today.day!=numberOfDays(today)){
		tomorrow.day=today.day+1;
		tomorrow.month=today.month;
		tomorrow.year=today.year;
	}else if(today.month==12){
		tomorrow.day=1;
		tomorrow.month=1;
		tomorrow.year=tomorrow.year+1;
	}else{
		tomorrow.day=1; 
		tomorrow.month=today.month+1;
		tomorrow.year=today.year;
	}
	printf("Tomorrow's date is %d-%d-%d.\n",tomorrow.year,tomorrow.month,tomorrow.day);
	return 0;
}
//通过输入的月份得到返回的天数 
int numberOfDays(struct date d)
{
	int days;
	const int daysPerMonth[12]={31,28,31,30,31,30,31,31,30,31,30,31}; 
	if(d.month==2&&isLeap(d)){
		days=29;
	}else{
		days=daysPerMonth[d.month-1];//数组下标-1 
	}
	return days;//单一出口 
} 
//判断2月有几天 
bool isLeap(struct date d)
{
	bool leap =false;
	if((d.year%4==0&&d.year%100!=0)||d.year%400==0){
		leap=true;
	}
	return leap;
}