py2exe编译后，如何取得exe的绝对路径

最新推荐文章于 2023-04-04 16:29:56 发布

morya

最新推荐文章于 2023-04-04 16:29:56 发布

阅读量2.2k

点赞数

文章标签： exe path encoding import windows file

本文链接：https://blog.youkuaiyun.com/morya/article/details/5612235

版权

本文介绍了一种在Python中无论是否通过py2exe编译，都能获取到程序所在目录绝对路径的方法。该方法对于运行在不同环境下的程序尤其有用，如在网站中定位静态资源文件或记录日志。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

py2exe编译后，如何取得exe的绝对路径

#!usr/bin/python #coding = utf-8 import sys import os def main_is_frozen(): """Return ''True'' if we're running from a frozen program.""" import imp return ( # new py2exe hasattr(sys, "frozen") or # tools/freeze imp.is_frozen("__main__")) def get_main_dir(): """Return the script directory - whether we're frozen or not.""" if main_is_frozen(): return os.path.abspath(os.path.dirname(sys.executable)) return os.path.abspath(os.path.dirname(sys.argv[0])) print get_main_dir()

官网的解决方案

http://www.py2exe.org/index.cgi/WhereAmI

You want to know WHERE your .exe is

Why? Maybe, you are building a website and have a subdir ./static below the directory in which your .exe resides, from where you server all .css and .js that is static. Or, you put the logs right below the programs dir within ./log

See also HowToDetermineIfRunningFromExe for a shorter recipe

上面的链接

See also WhereAmI for another take on this problem.

ThomasHeller posted this tip to the mailing list:

main_is_frozen() returns True when running the exe, and False when running from a script.

get_main_dir() returns the directory name of the script or the directory name of the exe - this is also sometimes useful.

切换行号显示

   1 
import
 imp
,
 os
,
 sys



   2 



   3 
def
 main_is_frozen
(
)
:



   4 
   return
 (
hasattr
(
sys
,
 "frozen"
)
 or
 # new py2exe



   5 
           hasattr
(
sys
,
 "importers"
)
 # old py2exe



   6 
           or
 imp
.
is_frozen
(
"__main__"
)
)
 # tools/freeze



   7 



   8 
def
 get_main_dir
(
)
:



   9 
   if
 main_is_frozen
(
)
:



  10 
       return
 os
.
path
.
dirname
(
sys
.
executable
)



  11 
   return
 os
.
path
.
dirname
(
sys
.
argv
[
0
]
)

--结束链接

Problem

You cannot rely on __file__ , because __file__ is not there in the py2exed main-script. You could try to rely on ".", the "Current Directory", but that only works if your application was started there. That may happen, but it is not guaranted.

Solution

import os

import jpath



if hasattr(sys,"frozen") and sys.frozen == "windows_exe":

    p=jpath.path(os.path.abspath(sys.executable)).dirname()

now p contains the directory where your exe resides, no matter from where your exe has been called (maybe it is in the path)

"jpath" is the famous path module from "Jason Orendorff"

Alternate Solution

The solution above will fail with a UnicodeDecodeError when using a Japanese (or Chinese/Korean, probably) version of Windows (XP + others?), and the path contains double-byte characters. This is because the sys.executable is in the file system encoding ('mbcs' on WinXP Japanese), and python tries to decode it to Unicode using the default Python encoding ('ascii'). The solution is to explicitly convert the path to Unicode using the default file system encoding. Additionally, checking only for a value of "windows_exe" will fail for a console application. I decided to live dangerously, and just test for "frozen" :-).

import os

import sys



def we_are_frozen():

    """Returns whether we are frozen via py2exe.

    This will affect how we find out where we are located."""



    return hasattr(sys, "frozen")





def module_path():

    """ This will get us the program's directory,

    even if we are frozen using py2exe"""



    if we_are_frozen():

        return os.path.dirname(unicode(sys.executable, sys.getfilesystemencoding( )))



    return os.path.dirname(unicode(__file__, sys.getfilesystemenco