“static“ base class members should not be accessed via derived types

项目场景：

Sonarlint 问题记录

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问题描述：

JSONObject.toJSONString()

在Sonarlint检查中发现提示：

“static” base class members should not be accessed via derived types

In the interest of code clarity, static members of a base class should never be accessed using a derived type’s name. Doing so is confusing and could create the illusion that two different static members exist.

意思是如果子类继承了父类的静态成员，不应该通过子类去调用

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解决方案：

改成父类的调用：

JSON.toJSONString()