Given a string s and a string t, check if s is subsequence of t.
You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and sis a short string (<=100).
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ace"
is a subsequence of "abcde"
while "aec"
is not).
Example 1:
s = "abc"
, t = "ahbgdc"
Return true
.
Example 2:
s = "axc"
, t = "ahbgdc"
Return false
.
设置两个循环,线性遍历,从s的第一个字符开始在t中遍历,如果在t中找到对应的字符,则改变标记变量进下一个字符的遍历,如果直到t遍历完都没找到,那么说明没有subsequence,返回false。如果全部遍历找到,那么返回true。
class Solution {
public:
bool isSubsequence(string s, string t)
{
int i,j,tail = 0;
for(i = 0;i < s.size(); i++)
{
for(j = tail; j < t.size(); j++)
{
if(s[i] == t[j])
{
tail = j+1;
break;
}
}
if(j == t.size())
return false;
}
return true;
}
};