前言:为了后续的实习面试,开始疯狂刷题,非常欢迎志同道合的朋友一起交流。因为时间比较紧张,目前的规划是先过一遍,写出能想到的最优算法,第二遍再考虑最优或者较优的方法。如有错误欢迎指正。博主首发优快云,mcf171专栏。
博客链接:mcf171的博客
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Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.
Follow up:
暂时没想出不用额外空间的方法。使用了O(m+n)的额外空间。
Your runtime beats 26.63% of java submissions.
Did you use extra space?
A straight forward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.
Could you devise a constant space solution?
public class Solution {
public void setZeroes(int[][] matrix) {
int m = matrix.length;
if( m == 0) return ;
int n = matrix[0].length;
int [] flag = new int [m+n];
for(int i = 0 ; i < m; i ++){
for(int j = 0 ; j < n ; j ++){
if(matrix[i][j] == 0){flag[i] = 1;flag[m+j] = 1;}
}
}
for( int i = 0 ; i < m+n; i++){
if(i<m){
if(flag[i] == 1){
for(int j = 0 ; j < n ;j ++) matrix[i][j] = 0;
}
}else{
if(flag[i] == 1){
for(int j = 0 ; j < m; j ++) matrix[j][i-m] = 0;
}
}
}
}
}